PUZZLE #4193: Monty Hall Cipher (diff 3)
The classic Monty Hall problem. You pick door #1. Host opens door #2 revealing a goat. Compute P(win by switching), multiply by 100, round to int, mod 26 (A=0) for the answer letter.
DATA
| Total Doors |
3
|
| Player Pick |
1
|
| Host Opens |
2
|
| Car Behind |
1
|
| Scenario |
You pick door #1. The host opens door #2 which has a goat. Should you switch to the remaining door?
|
| Formula |
P(win by switching) = 2/3
|
| Hint |
Monty Hall: with 3 doors, your initial pick has 1/3 chance of being right. The host reveals a goat. Switching wins if first pick was wrong (2/3). Compute int(P(switch) * 100). That mod 26 gives the answer letter (A=0).
|
| Answer Format |
single lowercase letter
|
author's note: Pool fill: monty-hall diff 3
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