PUZZLE #3475: Handshake Lemma (diff 6)
The Handshake Lemma states: in any graph, the sum of all vertex degrees equals twice the number of edges. Given the degree sequence [3, 2, 2, 1], compute the total number of handshakes (edges). The answer is the letter at position (edges mod 26).
DATA
| Degree Sequence |
3, 2, 2, 1
|
| Vertex Count |
4
|
| Hint |
Sum of degrees = 8. Divide by 2 to get edges = 4. Edges mod 26 = 4 → 'e'.
|
| Answer Format |
single lowercase letter
|
author's note: Pool fill: handshake-lemma diff 6
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