PUZZLE #4744: Chinese Remainder Cipher (diff 2)
Solve the system: x = 5 (mod 8), x = 4 (mod 15) where gcd(8, 15) = 1. Find x modulo 120. x mod 26 (A=0) is the answer letter.
DATA
| Congruences |
{'modulus': 8, 'remainder': 5}, {'modulus': 15, 'remainder': 4}
|
| M |
120
|
| Coprime |
True
|
| Formula |
x = a (mod 8), x = b (mod 15)
|
| Hint |
Solve: x = 5 (mod 8), x = 4 (mod 15) with gcd(8,15)=1. Unique solution modulo 120. x mod 26 (A=0) gives the answer letter.
|
| Answer Format |
single lowercase letter
|
author's note: Pool fill: chinese-remainder diff 2
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